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Good day Team, Question: A current of 4A flows in an inductor, and the energy stored by the inductor in joules is 12J, what will be the value of the inductor in henry? |
February 17, 2018 |
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Energy stored in the magnetic field of an inductor is $$E = \frac {1} {2} L I^2$$ So we can solve for $L$: $$L = \frac {2 E} {I^2}$$ or with your numbers: $$L = \frac {2 (12\ \text{J})} {(4\ \text{A})^2}= 1.5\ \text{H}$$ |
by mrobbins February 17, 2018 |
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