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In a PNP common base configuration circuit, how about if the circuit is set up at reverse configuration. Say no voltage source at emitter pin and just passive load. At collector pin there is voltage supplied. There would be base current at the base pin but will it be current flowing from collector to emitter?

Sounds like zero-zero if I understand you correctly. Can you give actual voltages wrt base?

A bias resistor at base pin is 5K to GND, voltage supplied at C pin is 3V

Sorry, I don't understand. Can you post full schematic surrounding that device?

The circuit looks like this : https://drive.google.com/open?id=1fV9PW6cXwjCE3ILMMEdMmIMQfujKlu5P

Definitely CB has current but I found current flowing at the emitter to the load resistor, not understand why.

From the picture, the bias conditions are following:

VE = 0V

VB = 0V

VC = 3V

Hence, you should observe no currents.

If you connect your PNP 'backwards' with reversed polarity, it looks roughly like two diodes, but not quite. You have biased the collector-base diode 'on', which puts the base at + 2.4 volts, with a current of 480 uA. The emitter-base diode is reverse-biased, and, were it just a diode, would pass no current. But there are a lot of carriers floating around and I suspect some are finding their way to the emitter. PNPs are not intended to work backwards. I suggest adding a diode in series with the emitter (or base) to block this effect.

PS - There may also be an emitter-collector diode inside the chip which is normally reverse-biased and which you are turning 'on'. You need to look at the chip structure, is it a vertical or a lateral PNP?

This may be relevant: http://www.joerg-berkner.de/Fachartikel/pdf/1999_ICCAP_UM_Berkner_Modeling_VPNP_using_Vbic.pdf . I'm just a dull old retired engineer and can't pretend to understand it.