I've been trying to get this simple circuit to work forever, but the voltages never come out right. How do I place the ground in the circuit? Because it makes the voltage over the resister 0 which screws up the voltage division. https://www.circuitlab.com/circuit/7z7sa6/voltage-division/ On paper: V1=4.27V V2=1.82V V3=3V V4=0.91V |
by wantafanta
April 18, 2012 |
I tried your circuit and it seems to simulate perfectly. I manually calculated the voltages and they agreed with CircuitLab... Try your paper calculations again? I got VA=5.727V VB-3.909V VC=909.1mV |
by anubi
April 18, 2012 |
I'm trying to figure out the voltage on each resistor, like this. http://circuits.solved-problems.com/482/voltage-divider-voltage-division-rule/ |
by wantafanta
April 19, 2012 |
You're both right but I think you're talking at cross purposes about which voltages are measured where. Does this help? :) |
by signality
April 19, 2012 |
Yes perfect! Alright last one lol, I tried setting up this circuit, I have the picture for it. But I can't get it to work either :( Here is the circuit I am going for, with the R=27k, C=0.1uF and Vs= 3 amplitude, 200 Hz, Square Wave http://s15.postimage.org/43j8f7acr/image.jpg This is what I created, but when I simulate it, it comes up wrong. Suppose to show 1 complete cycle of the AC so stop time = 0.005s |
by wantafanta
April 19, 2012 |
1) Don't forget the ground between V2 and V3. 2) You might want to run it for 0.05 sec and see a few cycles. C1 is "charged" to around -11 volts by the +3V from V1 along with the almost 4 gain of OA1 when the DC point is established. It takes a few cycles for it to stabilize to its new value with the AC drive. |
by anubi
April 19, 2012 |
by hellyeah
July 10, 2012 |
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Well, I looked at that. Now, what was your question? :) |
by signality
July 10, 2012 |
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