Created by | |
Created | March 31, 2013 |
Last modified | April 13, 2013 |
Tags | No tags. |
*TOTALY UNTESTED*
A trigger for a D800. The camera should be set off (Trigger Current goes high) when SW2 is open. If SW2 is closed, trigger current should be low.
Not provided.
You are shortening the 5V rail through R1, SW2 and the base-emiter junction of Q1. Why don't you connect the switch directly to the trigger pins of the camera? |
by adash
March 31, 2013 |
Well the trigger pin of the camera fires on a closed circuit. I'm trying to have it fire on an open circuit. Hmm this is my first time using this site. I didn't realize people looked through random public circuits. |
by revision17
April 01, 2013 |
Do you know what voltage level the camera triggers at? |
by adash
April 01, 2013 |
I know it triggers if the 2.8v trigger pin is connectedto ground. I'm going off this: http://www.alldigi.com/tag/nikon-10-pin-connector/ |
by revision17
April 01, 2013 |
Do you have the camera and a multimeter? If yes, can you measure the current to ground: Set the multimeter to 200mA, connect one probe to ground, connect the other to the shutter release pin. This would determine the needed base current for the switching transistor. Please also clarify - is the 5V supplied from the camera, or is it an external sourse. If it's supplied by the camera, check if it is available when the camera goes to sleep - the text in the link that you provided says that it's only available when the camera is awake. If so, an external battery would be needed. |
by adash
April 01, 2013 |
Please sign in or create an account to comment.
Only the circuit's creator can access stored revision history.