The LM317 requires a greater voltage on the input than the out. Since 0 volts is greater than negative this idea should work. R1 needs to be wired backwards on the negative side because more resistance means more output voltage. In this case 0 volts is more. We don't want that so we wire the pot backwards so the clockwise turn gives you less resistance. Just be sure to add filters and such.
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Again the same - LM317 can not sink current. You are going to get a nice regulated negative voltage, but not referenced to ground. |
April 03, 2013 |
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Thanks for the input Adash. This design is just a thought. I did bench test it with no load and had success. |
April 03, 2013 |
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Yeah, no load will be OK, since all of the "load" (voltmeter input resistance) will flow through the voltage divider R1/R2. See, you can visualize how such a circuit works, by trying to imagine how current flows out of the power source (V1), through the regulating element, through the load and back to the opposite pole of the V1. |
April 03, 2013 |
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